If you have a code that can execute any of the following complexity:
> O (n) sequence, for example: two O(n)
> O(n²)
The preferred version is the version that can be executed in linear time. Will there be a period of time O( There are too many sequences of n) and O(n²) would be more popular? In other words, the statement C x O(n)
>Big O is limited to n ->; therefore, in terms of big O, infinity, O(n)
I’m just not sure…
If you have one, you can do any of the following complex Sexual code:
> Sequence of O(n), for example: two O(n)
> O(n²)
The preferred version can be used in linear The version executed in time. Will there be too many O(n) sequences and O(n²) will be more popular for a while? In other words, the statement C x O(n)
I think there are two problems here; the first is what the symbol says, and the second is what is actually measured in the actual program
< p>>Big O as the limit is n –>; Therefore, in terms of big O, infinity, O(n)