Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given {32, 321, 3214, 0229, 87 }, we can recover many numbers such like 32-321 -3214-0229-87 or 0229-32-87-321-3214 with respect to different orders of combinations of these segments, and the smallest number is 0229-321-3214-32-87.
Input Specification:
Each input file contains one test case. Each case gives a positive integer < span class="strut">N (≤) followed by < span class="katex">N number segments. Each segment contains a non-negative integer of no more than 8 digits. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the smallest number in one line. Notice that the first digit must not be zero.
Sample Input:
5 32 321 3214 0229 87
Sample Output:
22932132143287
1 #include
2 #include <string>
3 #include
4 #include
5 using namespace std;
6 //Sequencing issues
7 int N;
8 vector<string>v, temp;
9 string res = "", str = "";
10 void permuteDFS(int u,vector<bool>&visit)//< /span>Use DFS
11 {
12 if (u == v.size())
13 {
14 for (auto a: temp)
15 str += a;
16 res = res> str ? str: res;
17 str = "";
18 return;
19 }
20 for (int i = 0; ii) 21 {
22 if (visit[i] == < span style="color: #0000ff;">true)continue;
23 visit[i] = true;
24 temp.push_back(v[i]);
25 permuteDFS(i + 1, visit);
26 temp.pop_back();
27 visit[i] = false;
28 }
29 }
30
31 void permutex(int u)//Use recursion
32 {
33 if (u == v.size())
34 {
35 for (auto a: v)
36 str += a;
37 res = res> str ? str: res;
38 str = "";
39 }
40 for (int i = u; ii)
41 {
42 swap(v[i], v[u]);
43 permutex(i + 1);
44 swap(v[i], v[u]);
45 }
46 }
47
48 void Sort()//Use sorting rules
49 {
50 sort(v.begin(), v.end(), [](string a, string b) {return a + b a; });
51 res = "";
52 for (auto a: v)
53 res += a;
54 }
55
56 int main()
57 {
58 cin >> N;
59 v.resize(N);
60 vector<bool>visit(N, < span style="color: #0000ff;">false);
61 for (int i = 0; ii)
62 {
63 cin >> v[i];
64 res += v[i];
65 }
66 //permutex(0);
67 //permuteDFS(0, visit);
68 Sort();
69 while (!res.empty() && res[0] == '0')
70 res.erase(0, 1);
71 if (res.size() == 0)cout << 0 ;
72 cout << res << endl;
73 return 0;
74 }
1 #include
2 #include <string>
3 #include
4 #include
5 using namespace std;
6 //Sequencing issues
7 int N;
8 vector<string>v, temp;
9 string res = "", str = "";
10 void permuteDFS(int u,vector<bool>&visit)//< /span>Use DFS
11 {
12 if (u == v.size())
13 {
14 for (auto a: temp)
15 str += a;
16 res = res> str ? str: res;
17 str = "";
18 return;
19 }
20 for (int i = 0; ii) 21 {
22 if (visit[i] == < span style="color: #0000ff;">true)continue;
23 visit[i] = true;
24 temp.push_back(v[i]);
25 permuteDFS(i + 1, visit);
26 temp.pop_back();
27 visit[i] = false;
28 }
29 }
30
31 void permutex(int u)//Use recursion
32 {
33 if (u == v.size())
34 {
35 for (auto a: v)
36 str += a;
37 res = res> str ? str: res;
38 str = "";
39 }
40 for (int i = u; ii)
41 {
42 swap(v[i], v[u]);
43 permutex(i + 1);
44 swap(v[i], v[u]);
45 }
46 }
47
48 void Sort()//Use sorting rules
49 {
50 sort(v.begin(), v.end(), [](string a, string b) {return a + b a; });
51 res = "";
52 for (auto a: v)
53 res += a;
54 }
55
56 int main()
57 {
58 cin >> N;
59 v.resize(N);
60 vector<bool>visit(N, < span style="color: #0000ff;">false);
61 for (int i = 0; ii)
62 {
63 cin >> v[i];
64 res += v[i];
65 }
66 //permutex(0);
67 //permuteDFS(0, visit);
68 Sort();
69 while (!res.empty() && res[0] == '0')
70 res.erase(0, 1);
71 if (res.size() == 0)cout << 0 ;
72 cout << res << endl;
73 return 0;
74 }