SWIFT – the key to the value of the value of the dictionary?

[
 0: "82" ,
 1: "12",
 2: "3",
 3: "42"
 // Etc.
]

[
 0: "3",
 1 : "12",
 2: "82",
 3: "42"
 // Etc.
]

var first_key = 0
var second_key = 2
var first_value = dict[first_key]!
var second_value = dict[second_key]!
dict[first_key ] = second_value
dict[second_key] = first_value

let tmp = dict[0]
dict[0] = dict[2]
dict[2] = tmp

var dict = [< br /> 0: "82",
 1: "12",
 2: "3",
 3: "42"
]

swap(&dict[0], &dict[2])

I have a dictionary in Swift, as shown below:

[
 0: "82",
 1: "12",
 2: "3",
 3: "42"
 // Etc.
]

And suppose I want to swap the keys to the values ​​82 and 3, so the new dictionary looks like this:

[
 0: "3",
 1: "12",
 2: "82",
 3: "42"
 // Etc.< br />]

What should I do? (I didn’t find any hints and don’t know how to do it, so I haven’t tried this code)

Edit:

I did this:

var first_key = 0
var second_key = 2
var first_value = dict[first_key]!
var second_value = dict[second_key]!
dict[first_key ] = second_value
dict[second_key] = first_value

The basic idea is to create a temporary variable to save one of the values ​​when swapping them. < p>

let tmp = dict[0]
dict[0] = dict[2]
dict[2] = tmp

Or you can use the global swap function (do the same operation internally).

var dict = [
 0: "82",
 1: "12",
 2: "3",
 3: "42"
]

swap(&dict[0], &dict[2] )