func getEndOfArray( arr: [T], fromIndex: Int? = 0) -> [T] {
var i=0;
var newArray : [T] = [T]()
for item in arr {
if i >= fromIndex {
newArray.append(item)
}
i = i + 1;
}
return newArray // returns copy of the array starting from index fromIndex
}
Is there a better way without additional functions?
< pre>let array = [1, 2, 3, 4, 5]
let fromIndex = 2
let endOfArray = array.dropFirst(fromIndex)
print(endOfArray) // [3, 4, 5]
This gives an ArraySlice, which should be good enough for most people
purpose. If you need a real array, please use
< /p>
let endOfArray = Array(array.dropFirst(fromIndex))
If the starting index is greater than (or equal to) the element count, create an empty array/slice.
There must be some very elegant way to use Swift to copy the end of the array from a certain index, but I couldn’t find it, so I ended up with this:
func getEndOfArray( arr: [T], fromIndex: Int? = 0) -> [T] {
var i=0;
var newArray: [ T] = [T]()
for item in arr {
if i >= fromIndex {
newArray.append(item)
}
i = i + 1;
}
return newArray // returns copy of the array starting from index fromIndex
}
Is there a better way without additional functions?
And the other…
let array = [1, 2, 3, 4, 5]
let fromIndex = 2
let endOfArray = array.dropFirst(fromIndex)
print(endOfArray) // [3, 4, 5]
This An ArraySlice was given, which should be good enough for most people
purpose. If you need a real array, please use
let endOfArray = Array(array .dropFirst(fromIndex))
If the starting index is greater than (or equal to) the element count, create an empty array/slice.
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