Leetcode # 11 Simple question (given a range, just hard coding ..)

Question: Integer to Roman Numerals

Question solution: The range is limited to 0-3999, hard-coded is good–too lazy to think about logic

class Solution {

public:

 string intToRoman(int num) {

 int a = num / 1000;

 int b = (num / 100)% < span style="color: #800080;">10;

 int c = (num / 10)% < span style="color: #800080;">10;

 int d = num% 10;

 string ans;

 for (int i = 0; i "M";

 if (b == 9)ans = ans + "CM" span>;

 else if (b == 8)ans = ans + "DCCC";

 else if (b == 7)ans = ans + "DCC span>";

 else if (b == 6)ans = ans + "DC";

 else if (b == 5)ans = ans + "D";

 else if (b == 4)ans = ans + "CD";

 else if (b == 3)ans = ans + "CCC";

 else if (b == 2)ans = ans + "CC";

 else if (b == 1)ans = ans + "C";



 if (c == 9)ans = ans + "XC" span>;

 else if (c == 8)ans = ans + "LXXX";

 else if (c == 7)ans = ans + "LXX";

 else if (c == 6)ans = ans + "LX";

 else if (c == 5)ans = ans + "L";

 else if (c == 4)ans = ans + "XL";

 else if (c == 3)ans = ans + "XXX";

 else if (c == 2)ans = ans + "XX";

 else if (c == 1)ans = ans + "X";



 if (d == 9)ans = ans + "IX" span>;

 else if (d == 8)ans = ans + "VIII";

 else if (d == 7)ans = ans + "VII";

 else if (d == 6)ans = ans + "VI";

 else if (d == 5)ans = ans + "V";

 else if (d == 4)ans = ans + "IV";

 else if (d == 3)ans = ans + "III";

 else if (d == 2)ans = ans + "II";

 else if (d == 1)ans = ans + "I";



 return ans;

}

};

class Solution {

public:

 string intToRoman(int num) {

 int a = num / 1000;

 int b = (num / 100)% < span style="color: #800080;">10;

 int c = (num / 10)% < span style="color: #800080;">10;

 int d = num% 10;

 string ans;

 for (int i = 0; i "M";

 if (b == 9)ans = ans + "CM" span>;

 else if (b == 8)ans = ans + "DCCC";

 else if (b == 7)ans = ans + "DCC span>";

 else if (b == 6)ans = ans + "DC";

 else if (b == 5)ans = ans + "D";

 else if (b == 4)ans = ans + "CD";

 else if (b == 3)ans = ans + "CCC";

 else if (b == 2)ans = ans + "CC";

 else if (b == 1)ans = ans + "C";



 if (c == 9)ans = ans + "XC" span>;

 else if (c == 8)ans = ans + "LXXX";

 else if (c == 7)ans = ans + "LXX";

 else if (c == 6)ans = ans + "LX";

 else if (c == 5)ans = ans + "L";

 else if (c == 4)ans = ans + "XL";

 else if (c == 3)ans = ans + "XXX";

 else if (c == 2)ans = ans + "XX";

 else if (c == 1)ans = ans + "X";



 if (d == 9)ans = ans + "IX" span>;

 else if (d == 8)ans = ans + "VIII";

 else if (d == 7)ans = ans + "VII";

 else if (d == 6)ans = ans + "VI";

 else if (d == 5)ans = ans + "V";

 else if (d == 4)ans = ans + "IV";

 else if (d == 3)ans = ans + "III";

 else if (d == 2)ans = ans + "II";

 else if (d == 1)ans = ans + "I";



 return ans;

}

};