# -*- coding: utf-8 -*-
x = (u 'abc/αβγ',)
print x
print x[0]
print unicode(x).encode('utf-8')
print x[0]. encode('utf-8')
…Production:
(u'abc/αβγ',)
abc/αβγ
(u'abc/αβγ',)
abc/αβγ
Is there a way to make Python print
p>
('abc/αβγ',)
Isn’t it necessary for me to construct the string representation of the tuple by myself? (I mean stringing “(“, “”, “encoded value”, “”, “,” and “)” together?
By the way, I am using Python 2.7. 1.
Thank you!
In [25]: print str(x).decode('raw_unicode_escape')
(u'abc/αβγ', )
The following code
# -*- coding: utf-8 -*-
x = (u'abc/αβγ',)
print x
print x[0]
print unicode(x).encode('utf-8')
print x[0].encode('utf-8')
…Production:
(u'abc/αβγ', )
abc/αβγ
(u'abc/αβγ',)
abc/αβγ
Is there a way to make Python print
('abc/αβγ',)
Does this do not require me to construct the string representation of the tuple by myself? (I mean “(“,”” , “Code value”, “”, “,” and “)” together?
By the way, I am using Python 2.7.1.
Thank you!< /p>
You can use’raw_unicode_escape’ to decode the str representation of the tuple.
In [25 ]: print str(x).decode('raw_unicode_escape')
(u'abc/αβγ',)