Regular expression – regular expression matches two unequal numbers

^P([1 -6]{1})([1-6]{1})$

^P([1-6]{1})(?!
)([1-6]{1}) $

 ^P((1[2-6])|(2[13-6])|(3[124-6])|(4[1-356])|(5[1-46])|(6 [1-5]))$

I want to know how to match two numbers, but not the same. So, match 12, but not 11, which would be great.

What I have up to now is:
I have to match a string like “P12”, I completed it with this regular expression:

^P([1-6]{1})([1-6]{1})$

But now my question is how to only match P12 or P32 like this The number does not repeat the string.

Any help or guidance on the reading material will be greatly appreciated.

Edit:
Thank you for your answers, but I am in RAD( radsoftware.com.au/regexdesigner) tested this-I know, I should mention this: /, and most of them are not working there. I saw a user posted a solution, but this is no longer visible, I I don’t know why, did he delete it? Anyway: this is valid:

^P([1-6]{1})(?!
)([1-6]{1}) $

Thank you!

Use this:

^P((1[2-6])| (2[13-6])|(3[124-6])|(4[1-356])|(5[1-46])|(6[1-5]))$