Convert XML strings to Python list

I am new to Python. I want to display this XML string as a list in a template.

xmlData = """ 


New Task
2
0


New Task
2
0


New ask
2
0


New Task
2
0
" ""

I just want to display it as a list.
I import cElementTree

from xml.etree import cElementTree as ET

I also did:

xmlList = ET.fromstring(xmlData)

But I don’t know how to display it. I want to display it like this Stuff.

print xmlList.name
print xmlList.mission_id
print xmlList.parent_task_id

Please help me know the correct syntax .

You can use this code example:

from xml.etree import cElementTree as ET
xml = ET.fromstring(xmlData)

for child in xml.iter('field'):
print child.tag, child.attrib, child.text

Iterate over all XML elements named field and print their tags, attributes and text values ​​to the console.

View< code>xml.etree documentation for more samples.

Django view

In order to present the parsed XML data as a view in a Django application, you need view and template.

Assuming that a Django application named app is installed in your project.

application/views.py

from xml.etr ee import cElementTree as ET

from django.http import HttpResponse
from django.shortcuts import render
from django.template import Context, loader

< br />def xml_view(request):
xmlData = """
< br />
foo
1
20


bar
2
10
"""

xml = ET.fromstring(xmlData)

fields = []
for obj in xml.iter("object"):
fields.append({'name' : obj.find("field[@nam e='name']").text,
'mission_id': obj.find("field[@name='mission_id']").text,
'parent_task_id': obj.find( "field[@name='parent_task_id']").text,
})

t = loader.get_template('your_app/xml_view.html')
c = Context ({'elem_list': fields})
return HttpResponse(t.render(c))

application/template/application/xml_view.html






< th>Mission ID


{% for elem in elem_list %}
< br />


{% endfor %}

I am new to Python. I want to display this XML string as a list in the template.

xmlData = """ 
< django-objects version="1.0">

New Task
2
0
< /object>

New Task
< field name="mission_id" type="IntegerField">2
0


New ask
2
0


New Task
2
0
"""

I just want to display it as a list.
I import cElementTree

from xml.etree import cElementTree as ET

I also do Out:

xmlList = ET.fromstring(xmlData)

But I don’t know how to show it. I want to show something like this.

print xmlList.name
print xmlList.mission_id
print xmlList.parent_task_id

Please help me know the correct syntax.

< /p>

You can use this code example:

from xml.etree import cElementTree as ET
xml = ET.fromstring(xmlData)

for child in xml.iter('field'):
print child.tag, child.attrib, child.text

Iterate all the XML elements named field and print their tags, attributes and text values ​​to the console.

Check out the xml.etree documentation for more samples.

Django view

In order to present the parsed XML data as a view in a Django application, you need view and template.

Assuming that your project has the name app’s Django application.

application/views.py

from xml.etree import cElementTree as ET

from django.http import HttpResponse
from django.shortcuts import render
from django.template import Context, loader


def xml_view(request):
xmlData = """


foo
1< br /> 20


bar
2
10
"""

xml = ET.fromstring(xmlData)

fields = []
for obj in xml.iter("object"):
fields.append({'name': obj.find("field[@name='name ']").text,
'mission_id': obj.find("field[@name='mission_id']").text,
'parent_task_id': obj.find("field[@ name='parent_task_id']").text,
})

t = loader.get_template('your_app/xml_view.html')
c = Context({'elem_list': fields})
return HttpResponse(t.render (c))

application/template/application/xml_view.html



Name Parent Task ID
{{ elem.name }} {{ elem.mission_id }} {{ elem.parent_task_id }}< /td>





{% for elem in elem_list %}





{% endfor% }

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Name Mission ID Parent Task ID< /th>
{{ elem.name }} {{ elem.mission_id }} {{ elem.parent_task_id }}