I have normal expressions
match = re.findall(r'[0-9]+(? :\.[0-9]+){3}', source)
It can get content similar to 192.168.1.1 from the source string.
How do I modify this regular expression to make It applies to things like this:
192.168.1.1:80
Thank you for your help.
P.S. Sorry, I English is not good.
This will match the IP address with the port number.
match = re.findall(r'[0-9]+(?:\.[0-9]+){3}:[0-9]+', source)
If you want to match the IP address flexibly without ports and ports, you can use:
match = re.findall( r'[0-9]+(?:\.[0-9]+){3}(:[0-9]+)?', source)
< p>I have a normal expression
match = re.findall(r'[0-9]+(?:\.[0-9]+ ){3}', source)
It can get something like 192.168.1.1 from the source string.
How do I modify this regular expression to make it suitable for things like this:
p>
192.168.1.1:80
Thank you for your help.
Attachment: Sorry, my English is not good.
This will match the IP address with the port number.
match = re.findall(r'[ 0-9]+(?:\.[0-9]+){3}:[0-9]+', source)
If you want to be flexible without ports and ports To match the IP address, you can use:
match = re.findall(r'[0-9]+(?:\.[0-9]+){ 3)( :[0-9]+)?', source)