PostgreSQL – PLPGSQL function returns another function value

CREATE OR REPLACE FUNCTION func2(mode integer )
 RETURNS integer AS
$$
begin
 if mode=1 then
 return func1(); - NOT plpgsql syntax
 end if;< br />
 more stuff .....

 return 2;
end
$$
LANGUAGE plpgsql VOLATILE

select func1() into temp;
return temp;

CREATE OR REPLACE FUNCTION func2(mode integer)
 RETURNS integer AS
 $BODY$
DECLARE 
 _result integer;
BEGIN
 _result = 2;
 IF mode=1 THEN
 _result = func1();
 END IF;

 --more stuff .....

 RETURN _result;
END
$BODY$
 LANGUAGE plpgsql VOLATILE COST 100;

CREATE OR REPLACE FUNCTION func2(mode integer)
 RETURNS integer AS
$BODY $
BEGIN
 IF mode=1 THEN
 RETURN func1();
 END IF;

 --more stuff .....

 RETURN 2;
END
$BODY$
 LANGUAGE plpgsql VOLATILE COST 100;

I have a function func1() returns an integer.

I want to write another function func2 (mode integer), which You can return func1()reults or do more things. The return value of func1() is of type INTEGER.

Such things:

CREATE OR REPLACE FUNCTION func2(mode integer)
 RETURNS integer AS
$$
begin
 if mode=1 then
 return func1(); - NOT plpgsql syntax
 end if;

 more stuff .....

 return 2;
end
$$
LANGUAGE plpgsql VOLATILE< /pre> 
My question is how do I return func1();? 
 
I know I can do it:
 
 
select func1() into temp;
return temp;
But If there is a more elegant way to do this, then I am thinking.

All these work: 
Option 1:

CREATE OR REPLACE FUNCTION func2(mode integer)
 RETURNS integer AS
$BODY$
DECLARE 
 _result integer;
BEGIN
 _result = 2;
 IF mode=1 THEN
 _result = func1();
 END IF;

 --more stuff .....

 RETURN _result;
END
$BODY$
 LANGUAGE plpgsql VOLATILE COST 100;
Options 2:

CREATE OR REPLACE FUNCTION func2(mode integer)
 RETURNS integer AS
$BODY$
BEGIN
 IF mode =1 THEN
 RETURN func1();
 END IF;

 --more stuff .....

 RETURN 2;
END
$BODY$
 LANGUAGE plpgsql VOLATILE COST 100;